Latest Pattern


Hello people this is the new pattern(2013) for TCS aptitude collected from 20 of my friends from NIT,SASTRA and TCE who wrote the exam. The new inclusions in the pattern is SUDOKU and puzzles. The old "70 pattern" is useless, its different now. Here are some points about the test.

The aptitude consisted of 30 QUESTIONS which were tuff for the most part. 
The test is for 80 minutes, total time(no timer for each question).
There is negative marking (the amount was not specified).
Most of my friends where able to attend only 20 questions due to time constraints(some of the questions were long ).
As far as i know there were no dummy questions,( but still beware i can't guarantee that if u attend dummy questions you are out for sure)

Here are some questions that were asked for the test. At least 15 questions will come out of this:



1) 28a + 30 b +31c =365 find a+b+c if a.b.c are natural numbers
Ans: If you observe carefully 28,30and 31 and no of days in the months of the year, which sums up to 365. so a,b,c represent number of days with 28,30 and 31 days in it so a=1,b=4,c=7 and a+b+c=12
2) P is 30% of Q
    Q is 20% of M
   M is 50% of N

what is P/N equal to.
Ans:p=30/100*q, q=20/100*m, m=50/100*n. So q=20/100*(50/100*n)substitution

and p = (30/100)*(20/100)*(50/100)*n and p/n =0.03

3)Mother +daughter+infant age is 74. Mother age is 46 more then daughter and infant.
And infant age is 0.4 of daughter. Find daughters age.
Ans:Let x be mothers age, y be daughters age and z infants. Then x+y+z=74, x=y+z+46 and z=0.4*y
substitute z in the main equation to get x+1.4y=74 and x-1.4y=46, solve these 2 to get y=10years
4) A takes 12 hrs to complete a work
    B takes 10 hrs to complete the same work 
    time taken by them to make 2 publications working independently.
Ans:calculate the rate of work A=1/12 and for B=1/10 if they work together then A+B=11/30 is rate of work, time taken to complete a 2 works together is 2/(11/30) which is 60/11 hrs

5)Some cards question. Probability of 1 ace which is red and one spade. Something like
This. Do go thru the cards ques. The decks and everything.
Ans:probability of getting a red ace and a spade card. So there are 52 cards in a deck out of which there are 2 red ace's so the probability of getting red ace is 2/52, then the probability of getting a spade from remaining cards is 13/51. The probability of getting both cards one after other is (2/52)*(13/51)=13/1326
6)A finishes a work in 8 hrs
   B finishes a work in 10 hrs
  C  finishes a work in 12 hrs
A,B,C work together but A leaves after 2 hrs find the time t taken by B & C.
Ans: effective rate of work A+B+C =1/8+1/10+1/12=37/120.so in 2 hours work completed by the three is 37/120*2=37/60.The remaining work is 1-37/60 that is 23/60. now only B and C are working together  so  1/10+1/12 = 11/60 is the rate of work. So time taken is 23/60(work remaining)/(11/60)= 2.09 hours approximately

7)There are exactly 4 Thursdays and 4 Sundays in a month of 31. Find the first day. 
You can calculate easily.
Ans: 1+4+7=12
becoz in a year there are 7 months of 31 days and 4 months of 30 days and 1 month of 29 or 28 days so
28*1+30*4+31*7=365

8)There were some questions of this type :-

J, K, L, M and N collected stamps. They collected a total of 100 stamps. None of them collected less than 10.
No two among them collected the same number.
(i) 3 collected the same number as K and M together.
(ii) L collected 3 more than the cube of an integer
(iii) The no. collected by J was the square of an integer.
(iv) Total no. collected by K was either the square or cube of an integer.
1. The no. collected by J was:
(1) 27 (2) 49 (3) 36 (4) 64
2. The no. collected by K was:
(1) 16 (2) 27 (3) 25 (4) 36
3. The difference of numbers collected by L & M was:
(1) 3 (2) 2 (3) 5 (4) 9

9)All numbers between 11 & 100 how many times is the number 4 used

10)A & B travelling from X to Y. A starts at 12 pm at a speed of 63m/hr. B at 1:30 pm at a speed of 84m/hr.At what time will B be 34m ahead of A?

11)There were2-3 visualizing questions also.

A cube was given in 1d. With dotted lines. Faces were marked. With 1 face as x. U had to
Tell that what will be face opposite x when it is folded as a cube.

12)Another time distance, a person runs around a rectangular field. Time given speed
Given. Find the distance. Apply perimeter formula 2(length+breadth). And length and breadth
Ratio given. Find area.


13)There is a school were 60% are girls and 35% of the girls are poor.
Students are selected at random, what is the probability of selecting a poor girl out of total strength.

14)There are 3 groups A,B,C 

2 members belong to all the three
3 members belong to A&B
3 members belong to B&C
3 members belong to C& A

minimum possible number of members in any three.

15)There are 3 numbers x,y,z 
the mean is m 
median is 5
m is 10 more than the smallest number and 15 less than the biggest number.
what is x+y+z

ANS: 30
let x be the smallest number then x=m-10
let z be biggest number then z=m+15
so y has to be the middle number and it says median is 5 so y = 5
now we make an equation:
x+y+z/3 = m ...........1 substituting
((m-10)+5+(m=15))/3=m solving we get m=10
substituting in equation 1
x+y+z= 3*m = 30

16)There are 5 men and 11 women. How many ways can a panel of 11 be formed such that the number of men is not more than 3.
Ans:2256
3m and 8 women =5C3*11C8
2m and 9 women =5C2*11C9
1m and 10 women = 5C1*11C10
0m and 11 women =5C0*11C11
Add all that to get 2256
17)Y-W-U-S-Q is coded as 25-23-21-19-17
what is S-F-A-Y-T coded as.

18) After 6 years Raju's fathers age will twice of the Raju's age 2 years ago.His mothers age was twice that of Raju's age. Sum of the age of their parents.

19)  Initial price =40,000. It reduces 3/4 of previous years price every year what is the price after 3 years.

20)60 men work take 40 days to complete a work. Now suppose that is 60 men start working and every 5 days 5 people leave.In how many days will the work be complete.

21)Then there was a series completion question.
7^0,7^1 , 7^1+7^0,7^2 something like this but i was not able to solve it. I tried to ask my friends for the exact questions but wasn't able to get it, anyways some series question with include finding the missing values will come

22)There was a triangle questions. There was a diagram of a triangle with multiple symmetric equilateral  triangle inside And they asked us how to many triangles there were in total
Description: E:\study material\tcsnew\INdia TCS NEW 2013 APTITUDE PATTERN!!_files\tri.png
23)Three groups :: x1,x2,x3
A,b common to all three. Then atleast 1 elemnt common to 2 ie x1,x2,x2,x3,x3,x1.
Findminimum elements in each group. 
Ans: is 4.

24)

Description: E:\study material\tcsnew\INdia TCS NEW 2013 APTITUDE PATTERN!!_files\c.png

         ok this is a a 2 paper cut u have to fold it into a cube and say what letter is on the opposite side of X. 
Ans: is C

25) Like sudoku type


Description: E:\study material\tcsnew\INdia TCS NEW 2013 APTITUDE PATTERN!!_files\c(1).png

u have to find a,b,e,c,d,f such that the sum of the sides are equal.

Ans: easiest way to do this is by substitution, you cant do this elsewise

26)Exact sudoku type question i don't remember the value it was a 3x3 matrix and u have to find value missing values in it.

27)3 dice are rolled. Then what is the probability u will get the sum of number as 10.
Ans :27/216

28) When all words in "master" is sorted in alphabetical order then what is the 49th word.
Ans: Using the letter's in master you fix a's position total no of words possible  is 5*4*3*2*1= 120 words. Now the next word in alphabetical order would start with "ae" the total number of words of that sort with first 2 letters fixed are 4*3*2*1=24, now the 25th word till 48th word will start with "am". So 49 word would be "aremst"  
a_ _ _ _ _ =120 words
a e _ _ _ _=24 words
a m _ _ _ _ =24 words 
"a r" is next in line so first word starting with "ar" and rest in alphabetical order is aremst

29)Some seating arrangement question. Like X sits opposites Y and B sits 2 seats left of A type questions. You are asked to find the person sitting 4 seats right of X.

30) 3 trucks A,B,C

A loads 10 kg/min
B loads 13 1/3 kg/min
C unloads 5kg/min

If three simultaneously works then what is the time taken to load 2.4 tonnes

Ans: First convert all to proper fraction so 13 1/3 = 40/3 kg/min Now work done by trucks together is:
A+B-C, so 10+13.3 - 5 = 18.3 kg/min. 2.4 tonnes is 2400 kg so time take is 2400/18.3 =131.1 minutes


BEST OF LUCK

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